HELP!!!the equation are of form of y = (x + h) square .

• scorchio

  27 Jun 06, 21:58

  the equation are of form of y = (x + h) square .
  comment on the effect of h on the graph of y = (x + h) square
• CoolMyth

  27 Jun 06, 22:44

  Quite simple what....
  
  Consider the equation y = x^2.
  
  Now think of when the curve y = x^2 meets the x-axis, the coordinate is at (0,0), right?
  
  Now, think of say y = (x + 2)^2. Note that this time, this curve meets the x-axis at the coordinate (-2, 0) (Take y = 0 and solve)
  
  Think of a third case (x + (-2))^2. It meets the x-axis at coordinate (2,0)
  
  So, looking at the big picture, the curve stays the same but there's a translation of h units left or right of the origin from y = x^2, depending on whether h is positive or negative.
• scorchio

  28 Jun 06, 00:00

  thanks a million dude!!
• Ito_^

  28 Jun 06, 00:07

  
• mhcampboy

  28 Jun 06, 00:11

  
  
  so chim!!... can join my friends to the maths olympiad already...