erm ok use 1 and 2Originally posted by CoolMyth:Ever thought why this is true? Now try your hand at proving it.
Some hints:
Let a, b and c be numbers and -a, -b and -c be its negative respectively.
i) a + (-a) = 0 (Obvious, right? )
ii) a*(b+c) = a*b + a*c
iii) a + c = b + c <--> a = b
Okay, now try proving (-1) * (-1) = 1 using the above hints. But in your proof, don't ever use (-1) * (-1) = 1.
By shifting the part in red to the other side, you're indirectly implying thatOriginally posted by hisoka:erm ok use 1 and 2
b=a and c = -a
so a^2 +a(-a) = 0
a^2= (-1).(-1).a^2
therefore (-1).(-1) = 1??
huh?? dun get what you meanOriginally posted by CoolMyth:By shifting the part in red to the other side, you're indirectly implying that
1 = -(-1) = (-1) * (-1), which is the question itself.
So, it's not correct, sorry, but it's a good effort.
Note, a, b and c are just numbers, you're supposed to substitute appropriate values for them and use the hints given.
EDIT: Finally saw something wrong.Originally posted by hisoka:huh?? dun get what you mean
what i did was to add both sides with the term i wanna appear on the right so no implied of the 1 =-(-1)
wrong marking request to strip you of jobOriginally posted by CoolMyth:EDIT by mod: see above
you never say cannot use other such terms worOriginally posted by CoolMyth:EDIT: Finally saw something wrong.
Okay. Here's how it goes:
You were actually using the fact that (-1)a = -a, which is not of my hints given.
Sorry.
I got say use the above hints mah.Originally posted by hisoka:you never say cannot use other such terms wor